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4x^2-62x+220=0
a = 4; b = -62; c = +220;
Δ = b2-4ac
Δ = -622-4·4·220
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-18}{2*4}=\frac{44}{8} =5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+18}{2*4}=\frac{80}{8} =10 $
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